Quiz : Maîtrisez les bases des équations et calculs en 3ème année secondaire
🧠 Quiz 10 questions 10 min
QUIZ INTERACTIFDiff. 5/10
Correction détaillée des exercices de mathématiques de la semaine 1 pour la 3ème année secondaire. Solutions expliquées et conseils pour progresser.
Question 1 sur 10 10:00
[{"id":34543,"question":"Quelle est la solution de l'équation 3x - 5 = 7 ?","option_a":"x = 4","option_b":"x = 12\/3","option_c":"x = 4\/3","option_d":"x = 2","option_e":"","option_f":"","bonne_reponse":"A","explication":"Pour résoudre 3x - 5 = 7, on ajoute 5 des deux côtés : 3x = 12, puis on divise par 3 : x = 4.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0},{"id":34544,"question":"L'équation x² = 16 a deux solutions réelles.","option_a":"Vrai","option_b":"Faux","option_c":"","option_d":"","option_e":"","option_f":"","bonne_reponse":"A","explication":"x² = 16 équivaut à x = 4 ou x = -4, donc il y a bien deux solutions réelles.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0},{"id":34545,"question":"Quelle est la forme développée de (x + 3)(x - 2) ?","option_a":"x² + x - 6","option_b":"x² - 6x + 1","option_c":"x² + 5x - 6","option_d":"x² + x + 6","option_e":"","option_f":"","bonne_reponse":"A","explication":"En développant (x + 3)(x - 2), on obtient x² - 2x + 3x - 6 = x² + x - 6.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0},{"id":34546,"question":"La fonction f(x) = 2x + 1 est-elle linéaire ?","option_a":"Vrai","option_b":"Faux","option_c":"","option_d":"","option_e":"","option_f":"","bonne_reponse":"A","explication":"Une fonction linéaire s'écrit f(x) = ax, donc f(x) = 2x + 1 est affine, pas linéaire.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0},{"id":34547,"question":"Résoudre l'inéquation 2x - 3 \u003E 5.","option_a":"x \u003E 4","option_b":"x \u003E 1","option_c":"x \u003C 4","option_d":"x \u003E 8","option_e":"","option_f":"","bonne_reponse":"A","explication":"2x - 3 \u003E 5 ⇒ 2x \u003E 8 ⇒ x \u003E 4.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0},{"id":34548,"question":"Le discriminant d'une équation du second degré ax² + bx + c = 0 est donné par Δ = b² - 4ac.","option_a":"Vrai","option_b":"Faux","option_c":"","option_d":"","option_e":"","option_f":"","bonne_reponse":"A","explication":"La formule du discriminant est bien Δ = b² - 4ac.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0},{"id":34549,"question":"Quelle est la valeur de x si 5x = 20 ?","option_a":"x = 4","option_b":"x = 5","option_c":"x = 100","option_d":"x = 15","option_e":"","option_f":"","bonne_reponse":"A","explication":"5x = 20 ⇒ x = 20 \/ 5 = 4.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0},{"id":34550,"question":"L'expression 3(x + 2) est-elle équivalente à 3x + 6 ?","option_a":"Vrai","option_b":"Faux","option_c":"","option_d":"","option_e":"","option_f":"","bonne_reponse":"A","explication":"En développant 3(x + 2), on obtient 3x + 6, donc les deux expressions sont équivalentes.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0},{"id":34551,"question":"Résoudre l'équation (x - 1)(x + 3) = 0.","option_a":"x = 1 ou x = -3","option_b":"x = -1 ou x = 3","option_c":"x = 0 ou x = 2","option_d":"x = 1 ou x = 3","option_e":"","option_f":"","bonne_reponse":"A","explication":"Un produit de facteurs est nul si l'un des facteurs est nul : x - 1 = 0 ⇒ x = 1 ou x + 3 = 0 ⇒ x = -3.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0},{"id":34552,"question":"La fonction f(x) = x² est-elle croissante sur ℝ ?","option_a":"Vrai","option_b":"Faux","option_c":"","option_d":"","option_e":"","option_f":"","bonne_reponse":"B","explication":"La fonction f(x) = x² est décroissante sur ]-∞; 0] et croissante sur [0; +∞[, donc elle n'est pas croissante sur tout ℝ.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0}]
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