Quiz : Maîtrisez les équations et fonctions en 2ème année secondaire !

Question 1 sur 10 10:00

[{"id":53971,"question":"Quelle est la solution de l'équation 3x - 5 = 7 ?","option_a":"x = 4","option_b":"x = 12","option_c":"x = 2","option_d":"x = -4","option_e":"","option_f":"","bonne_reponse":"A","explication":"Pour résoudre 3x - 5 = 7, on ajoute 5 des deux côtés : 3x = 12, puis on divise par 3 : x = 4.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0},{"id":53972,"question":"L'équation x² - 4x + 4 = 0 admet-elle deux solutions distinctes ?","option_a":"Vrai","option_b":"Faux","option_c":"","option_d":"","option_e":"","option_f":"","bonne_reponse":"B","explication":"Cette équation est un carré parfait : (x - 2)² = 0, donc elle admet une solution double x = 2.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0},{"id":53973,"question":"Quelle est la forme factorisée de x² - 9 ?","option_a":"(x - 3)(x + 3)","option_b":"(x - 9)(x + 1)","option_c":"(x - 3)²","option_d":"(x + 3)²","option_e":"","option_f":"","bonne_reponse":"A","explication":"x² - 9 est une différence de carrés : (x - 3)(x + 3).","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0},{"id":53974,"question":"La fonction f(x) = 2x + 1 est-elle une fonction affine ?","option_a":"Vrai","option_b":"Faux","option_c":"","option_d":"","option_e":"","option_f":"","bonne_reponse":"A","explication":"Une fonction affine s'écrit f(x) = ax + b, ici a = 2 et b = 1, donc c'est bien une fonction affine.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0},{"id":53975,"question":"Quelle est la solution de l'inéquation 2x + 3 ≤ 7 ?","option_a":"x ≤ 2","option_b":"x ≥ 2","option_c":"x ≤ -2","option_d":"x ≥ -2","option_e":"","option_f":"","bonne_reponse":"A","explication":"2x + 3 ≤ 7 → 2x ≤ 4 → x ≤ 2.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0},{"id":53976,"question":"La représentation graphique d'une fonction affine est toujours une droite ?","option_a":"Vrai","option_b":"Faux","option_c":"","option_d":"","option_e":"","option_f":"","bonne_reponse":"A","explication":"Oui, car une fonction affine est de la forme f(x) = ax + b, dont le graphe est une droite.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0},{"id":53977,"question":"Quelle est la valeur de x dans l'équation 4(x - 1) = 2x + 6 ?","option_a":"x = 5","option_b":"x = 3","option_c":"x = -1","option_d":"x = 2","option_e":"","option_f":"","bonne_reponse":"A","explication":"4x - 4 = 2x + 6 → 2x = 10 → x = 5.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0},{"id":53978,"question":"La fonction f(x) = x² est-elle paire ?","option_a":"Vrai","option_b":"Faux","option_c":"","option_d":"","option_e":"","option_f":"","bonne_reponse":"A","explication":"Une fonction est paire si f(-x) = f(x). Ici, f(-x) = (-x)² = x² = f(x), donc oui.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0},{"id":53979,"question":"Quelle est la solution de l'équation (x + 2)(x - 3) = 0 ?","option_a":"x = -2 ou x = 3","option_b":"x = 2 ou x = -3","option_c":"x = 1 ou x = -1","option_d":"x = 0","option_e":"","option_f":"","bonne_reponse":"A","explication":"Un produit de facteurs est nul si l'un des facteurs est nul : x + 2 = 0 ou x - 3 = 0.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0},{"id":53980,"question":"La fonction f(x) = 1\/x est-elle définie pour x = 0 ?","option_a":"Vrai","option_b":"Faux","option_c":"","option_d":"","option_e":"","option_f":"","bonne_reponse":"B","explication":"La fonction f(x) = 1\/x n'est pas définie en x = 0 car la division par zéro est impossible.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0}]