Quiz — séries physiques.pdf

Question 1 sur 10 20:00

[{"id":138431,"question":"Quelle est l'unité SI de la force dans le système international ?","option_a":"Newton (N)","option_b":"Joule (J)","option_c":"Watt (W)","option_d":"Pascal (Pa)","option_e":"","option_f":"","bonne_reponse":"a","explication":"L'unité SI de la force est le Newton (N), en hommage à Isaac Newton pour ses lois du mouvement.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"a\", \"options\": {\"a\": \"Newton (N)\", \"b\": \"Joule (J)\", \"c\": \"Watt (W)\", \"d\": \"Pascal (Pa)","_debug_options_count":4},{"id":138432,"question":"La loi d'Ohm s'applique uniquement aux conducteurs ohmiques.","option_a":"Vrai","option_b":"Faux","option_c":"","option_d":"","option_e":"","option_f":"","bonne_reponse":"a","explication":"La loi d'Ohm (U = R×I) est valable uniquement pour les conducteurs ohmiques, où la résistance est constante.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"a\", \"options\": {\"a\": \"Vrai\", \"b\": \"Faux\", \"c\": \"\", \"d\": \"\"}}","_debug_options_count":4},{"id":138433,"question":"Quel phénomène physique explique la formation d'un arc-en-ciel ?","option_a":"La diffraction","option_b":"La réflexion","option_c":"La réfraction","option_d":"L'interférence","option_e":"","option_f":"","bonne_reponse":"c","explication":"L'arc-en-ciel est dû à la réfraction de la lumière blanche dans les gouttes d'eau, suivie d'une réflexion interne.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"c\", \"options\": {\"a\": \"La diffraction\", \"b\": \"La réflexion\", \"c\": \"La réfraction\", \"d\"","_debug_options_count":4},{"id":138434,"question":"Calculez la puissance électrique dissipée par un conducteur ohmique de résistance 10 Ω traversé par un courant de 2 A.","option_a":"20 W","option_b":"40 W","option_c":"100 W","option_d":"5 W","option_e":"","option_f":"","bonne_reponse":"b","explication":"La puissance P = R×I² = 10 × (2)² = 40 W.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"b\", \"options\": {\"a\": \"20 W\", \"b\": \"40 W\", \"c\": \"100 W\", \"d\": \"5 W\"}}","_debug_options_count":4},{"id":138435,"question":"Un corps en mouvement circulaire uniforme a une accélération centripète.","option_a":"Vrai","option_b":"Faux","option_c":"","option_d":"","option_e":"","option_f":"","bonne_reponse":"a","explication":"Un mouvement circulaire uniforme implique une accélération centripète dirigée vers le centre de la trajectoire.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"a\", \"options\": {\"a\": \"Vrai\", \"b\": \"Faux\", \"c\": \"\", \"d\": \"\"}}","_debug_options_count":4},{"id":138436,"question":"Quelle est la relation entre la fréquence (f) et la période (T) d'un phénomène périodique ?","option_a":"f = T","option_b":"f = 1\/T","option_c":"f = T²","option_d":"f = 2πT","option_e":"","option_f":"","bonne_reponse":"b","explication":"La fréquence est l'inverse de la période : f = 1\/T (en Hz si T est en secondes).","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"b\", \"options\": {\"a\": \"f = T\", \"b\": \"f = 1\/T\", \"c\": \"f = T²\", \"d\": \"f = 2πT\"}}","_debug_options_count":4},{"id":138437,"question":"Un miroir plan donne toujours une image virtuelle et de même taille que l'objet.","option_a":"Vrai","option_b":"Faux","option_c":"","option_d":"","option_e":"","option_f":"","bonne_reponse":"a","explication":"Un miroir plan produit une image virtuelle, droite et de même taille que l'objet.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"a\", \"options\": {\"a\": \"Vrai\", \"b\": \"Faux\", \"c\": \"\", \"d\": \"\"}}","_debug_options_count":4},{"id":138438,"question":"Quelle loi physique exprime la conservation de l'énergie mécanique dans un système isolé ?","option_a":"Loi de Newton","option_b":"Loi de conservation de la quantité de mouvement","option_c":"Théorème de l'énergie cinétique","option_d":"Loi de conservation de l'énergie mécanique","option_e":"","option_f":"","bonne_reponse":"d","explication":"Dans un système isolé, l'énergie mécanique (cinétique + potentielle) se conserve.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"d\", \"options\": {\"a\": \"Loi de Newton\", \"b\": \"Loi de conservation de la quantité de mouv","_debug_options_count":4},{"id":138439,"question":"Calculez l'énergie cinétique d'un corps de masse 2 kg se déplaçant à une vitesse de 3 m\/s.","option_a":"9 J","option_b":"18 J","option_c":"6 J","option_d":"3 J","option_e":"","option_f":"","bonne_reponse":"b","explication":"L'énergie cinétique Ec = ½ × m × v² = ½ × 2 × (3)² = 9 J.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"b\", \"options\": {\"a\": \"9 J\", \"b\": \"18 J\", \"c\": \"6 J\", \"d\": \"3 J\"}}","_debug_options_count":4},{"id":138440,"question":"La résistance électrique d'un conducteur dépend de sa longueur et de sa section.","option_a":"Vrai","option_b":"Faux","option_c":"","option_d":"","option_e":"","option_f":"","bonne_reponse":"a","explication":"La résistance R = ρ × (L\/S), où ρ est la résistivité, L la longueur et S la section.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"a\", \"options\": {\"a\": \"Vrai\", \"b\": \"Faux\", \"c\": \"\", \"d\": \"\"}}","_debug_options_count":4}]