Quiz — M-PT-PVS-JMF-4.pdf

Question 1 sur 10 20:00

[{"id":46453,"question":"Quelle est l'unité de la constante de Planck (h) dans le système international ?","option_a":"J.s","option_b":"kg.m².s⁻¹","option_c":"C.V","option_d":"N.m","option_e":"","option_f":"","bonne_reponse":"a","explication":"La constante de Planck s'exprime en joule-seconde (J.s) dans le système international.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"a\", \"options\": {\"a\": \"J.s\", \"b\": \"kg.m².s⁻¹\", \"c\": \"C.V\", \"d\": \"N.m\"}}","_debug_options_count":4},{"id":46454,"question":"La deuxième loi de Newton s'écrit : ΣF = m.a. Vrai ou Faux ?","option_a":"Vrai","option_b":"Faux","option_c":"","option_d":"","option_e":"","option_f":"","bonne_reponse":"a","explication":"La deuxième loi de Newton affirme que la somme des forces est égale à la masse multipliée par l'accélération (ΣF = m.a).","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"a\", \"options\": {\"a\": \"Vrai\", \"b\": \"Faux\", \"c\": \"\", \"d\": \"\"}}","_debug_options_count":4},{"id":46455,"question":"Quel phénomène physique explique la formation d'un arc-en-ciel ?","option_a":"La diffraction","option_b":"La réflexion","option_c":"La réfraction","option_d":"L'interférence","option_e":"","option_f":"","bonne_reponse":"c","explication":"L'arc-en-ciel est dû à la réfraction et à la dispersion de la lumière blanche par les gouttes d'eau.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"c\", \"options\": {\"a\": \"La diffraction\", \"b\": \"La réflexion\", \"c\": \"La réfraction\", \"d\"","_debug_options_count":4},{"id":46456,"question":"La tension aux bornes d'un conducteur ohmique est proportionnelle à l'intensité du courant qui le traverse. Vrai ou Faux ?","option_a":"Vrai","option_b":"Faux","option_c":"","option_d":"","option_e":"","option_f":"","bonne_reponse":"a","explication":"C'est la loi d'Ohm : U = R.I, où U est la tension, R la résistance et I l'intensité.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"a\", \"options\": {\"a\": \"Vrai\", \"b\": \"Faux\", \"c\": \"\", \"d\": \"\"}}","_debug_options_count":4},{"id":46457,"question":"Quelle est la relation entre la période T et la fréquence f d'un signal périodique ?","option_a":"T = f","option_b":"T = 1\/f","option_c":"T = f²","option_d":"T = 2πf","option_e":"","option_f":"","bonne_reponse":"b","explication":"La période T est l'inverse de la fréquence : T = 1\/f.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"b\", \"options\": {\"a\": \"T = f\", \"b\": \"T = 1\/f\", \"c\": \"T = f²\", \"d\": \"T = 2πf\"}}","_debug_options_count":4},{"id":46458,"question":"Un électron accéléré dans un champ électrique uniforme gagne de l'énergie cinétique. Vrai ou Faux ?","option_a":"Vrai","option_b":"Faux","option_c":"","option_d":"","option_e":"","option_f":"","bonne_reponse":"a","explication":"L'électron, chargé négativement, est accéléré par le champ électrique et gagne de l'énergie cinétique.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"a\", \"options\": {\"a\": \"Vrai\", \"b\": \"Faux\", \"c\": \"\", \"d\": \"\"}}","_debug_options_count":4},{"id":46459,"question":"Quelle est la valeur de la célérité de la lumière dans le vide (c) ?","option_a":"3.10⁸ m\/s","option_b":"3.10⁵ km\/s","option_c":"3.10⁸ km\/h","option_d":"2.10⁸ m\/s","option_e":"","option_f":"","bonne_reponse":"a","explication":"La célérité de la lumière dans le vide est d'environ 3.10⁸ mètres par seconde.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"a\", \"options\": {\"a\": \"3.10⁸ m\/s\", \"b\": \"3.10⁵ km\/s\", \"c\": \"3.10⁸ km\/h\", \"d\": \"2.1","_debug_options_count":4},{"id":46460,"question":"La force magnétique sur une particule chargée est toujours perpendiculaire à sa vitesse. Vrai ou Faux ?","option_a":"Vrai","option_b":"Faux","option_c":"","option_d":"","option_e":"","option_f":"","bonne_reponse":"a","explication":"La force magnétique (Lorentz) est toujours perpendiculaire à la vitesse de la particule chargée.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"a\", \"options\": {\"a\": \"Vrai\", \"b\": \"Faux\", \"c\": \"\", \"d\": \"\"}}","_debug_options_count":4},{"id":46461,"question":"Quelle est l'expression de l'énergie cinétique Ec d'un corps de masse m et de vitesse v ?","option_a":"Ec = m.v","option_b":"Ec = ½.m.v²","option_c":"Ec = m.v²","option_d":"Ec = m.g.h","option_e":"","option_f":"","bonne_reponse":"b","explication":"L'énergie cinétique est donnée par Ec = ½.m.v².","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"b\", \"options\": {\"a\": \"Ec = m.v\", \"b\": \"Ec = ½.m.v²\", \"c\": \"Ec = m.v²\", \"d\": \"Ec = m.","_debug_options_count":4},{"id":46462,"question":"Un miroir sphérique concave peut former une image réelle d'un objet réel. Vrai ou Faux ?","option_a":"Vrai","option_b":"Faux","option_c":"","option_d":"","option_e":"","option_f":"","bonne_reponse":"a","explication":"Un miroir concave peut former une image réelle si l'objet est placé au-delà du foyer.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"a\", \"options\": {\"a\": \"Vrai\", \"b\": \"Faux\", \"c\": \"\", \"d\": \"\"}}","_debug_options_count":4}]