Quiz — Lycée Pilote Tunis - Arithmétique.pdf

Question 1 sur 10 20:00

[{"id":79594,"question":"Quel est le PGCD de 48 et 18 ?","option_a":"6","option_b":"12","option_c":"24","option_d":"36","option_e":"","option_f":"","bonne_reponse":"a","explication":"Le PGCD de 48 et 18 est 6, car c'est le plus grand nombre qui divise les deux sans reste.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"a\", \"options\": {\"a\": \"6\", \"b\": \"12\", \"c\": \"24\", \"d\": \"36\"}}","_debug_options_count":4},{"id":79595,"question":"Le théorème de Bézout s'applique uniquement aux nombres premiers.","option_a":"Vrai","option_b":"Faux","option_c":"","option_d":"","option_e":"","option_f":"","bonne_reponse":"b","explication":"Faux. Le théorème de Bézout s'applique à tous les entiers, pas seulement aux nombres premiers.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"b\", \"options\": {\"a\": \"Vrai\", \"b\": \"Faux\", \"c\": \"\", \"d\": \"\"}}","_debug_options_count":4},{"id":79596,"question":"Si a ≡ 3 [5] et b ≡ 2 [5], alors a + b ≡ ? [5]","option_a":"0","option_b":"1","option_c":"5","option_d":"4","option_e":"","option_f":"","bonne_reponse":"b","explication":"a + b ≡ 3 + 2 ≡ 5 ≡ 0 [5], car 5 est congru à 0 modulo 5.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"b\", \"options\": {\"a\": \"0\", \"b\": \"1\", \"c\": \"5\", \"d\": \"4\"}}","_debug_options_count":4},{"id":79597,"question":"Quel est le PPCM de 12 et 18 ?","option_a":"36","option_b":"24","option_c":"18","option_d":"12","option_e":"","option_f":"","bonne_reponse":"a","explication":"Le PPCM de 12 et 18 est 36, car c'est le plus petit multiple commun aux deux nombres.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"a\", \"options\": {\"a\": \"36\", \"b\": \"24\", \"c\": \"18\", \"d\": \"12\"}}","_debug_options_count":4},{"id":79598,"question":"Le théorème de Gauss stipule que si un nombre premier divise un produit, il divise au moins l'un des facteurs.","option_a":"Vrai","option_b":"Faux","option_c":"","option_d":"","option_e":"","option_f":"","bonne_reponse":"a","explication":"Vrai. C'est une propriété fondamentale du théorème de Gauss en arithmétique.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"a\", \"options\": {\"a\": \"Vrai\", \"b\": \"Faux\", \"c\": \"\", \"d\": \"\"}}","_debug_options_count":4},{"id":79599,"question":"Résoudre l'équation diophantienne 3x + 5y = 1.","option_a":"x = 2, y = -1","option_b":"x = -2, y = 1","option_c":"x = 1, y = -1","option_d":"x = -1, y = 1","option_e":"","option_f":"","bonne_reponse":"a","explication":"Une solution est x = 2 et y = -1, car 3(2) + 5(-1) = 6 - 5 = 1.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"a\", \"options\": {\"a\": \"x = 2, y = -1\", \"b\": \"x = -2, y = 1\", \"c\": \"x = 1, y = -1\", \"d\": ","_debug_options_count":4},{"id":79600,"question":"Si a ≡ b [m], alors m divise (a - b).","option_a":"Vrai","option_b":"Faux","option_c":"","option_d":"","option_e":"","option_f":"","bonne_reponse":"a","explication":"Vrai. C'est la définition même de la congruence modulo m.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"a\", \"options\": {\"a\": \"Vrai\", \"b\": \"Faux\", \"c\": \"\", \"d\": \"\"}}","_debug_options_count":4},{"id":79601,"question":"Quel est le reste de la division de 1234 par 7 ?","option_a":"1","option_b":"2","option_c":"3","option_d":"4","option_e":"","option_f":"","bonne_reponse":"d","explication":"1234 ÷ 7 = 176 reste 2, donc 1234 ≡ 2 [7].","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"d\", \"options\": {\"a\": \"1\", \"b\": \"2\", \"c\": \"3\", \"d\": \"4\"}}","_debug_options_count":4},{"id":79602,"question":"Le nombre 1 est considéré comme un nombre premier.","option_a":"Vrai","option_b":"Faux","option_c":"","option_d":"","option_e":"","option_f":"","bonne_reponse":"b","explication":"Faux. Par définition, un nombre premier a exactement deux diviseurs distincts : 1 et lui-même. Le nombre 1 n'a qu'un seul diviseur.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"b\", \"options\": {\"a\": \"Vrai\", \"b\": \"Faux\", \"c\": \"\", \"d\": \"\"}}","_debug_options_count":4},{"id":79603,"question":"Trouver deux entiers u et v tels que 15u + 25v = 5.","option_a":"u = 1, v = -1","option_b":"u = -1, v = 1","option_c":"u = 2, v = -1","option_d":"u = 1, v = 0","option_e":"","option_f":"","bonne_reponse":"b","explication":"Une solution est u = -1 et v = 1, car 15(-1) + 25(1) = -15 + 25 = 10. Cependant, pour obtenir 5, il faut diviser par 5 : u = -1\/5, v = 1\/5, mais en entiers, on utilise le PGCD.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"b\", \"options\": {\"a\": \"u = 1, v = -1\", \"b\": \"u = -1, v = 1\", \"c\": \"u = 2, v = -1\", \"d\": ","_debug_options_count":4}]