Quiz — 1569078035_3-Calcul dans C .pdf

Question 1 sur 10 20:00

[{"id":53024,"question":"Quel est le conjugué du nombre complexe z = 3 - 4i ?","option_a":"3 + 4i","option_b":"-3 + 4i","option_c":"4 + 3i","option_d":"-4 - 3i","option_e":"","option_f":"","bonne_reponse":"a","explication":"Le conjugué d'un nombre complexe z = a + bi est noté \\overline{z} = a - bi. Ici, a = 3 et b = -4, donc \\overline{z} = 3 + 4i.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"a\", \"options\": {\"a\": \"3 + 4i\", \"b\": \"-3 + 4i\", \"c\": \"4 + 3i\", \"d\": \"-4 - 3i\"}}","_debug_options_count":4},{"id":53025,"question":"Vrai ou Faux ? Le module d'un nombre complexe est toujours un nombre réel positif.","option_a":"Vrai","option_b":"Faux","option_c":"","option_d":"","option_e":"","option_f":"","bonne_reponse":"a","explication":"Le module |z| = √(a² + b²) est toujours un nombre réel positif ou nul, car c'est une racine carrée d'une somme de carrés.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"a\", \"options\": {\"a\": \"Vrai\", \"b\": \"Faux\", \"c\": \"\", \"d\": \"\"}}","_debug_options_count":4},{"id":53026,"question":"Quelle est la forme trigonométrique de z = -1 + i√3 ?","option_a":"2(cos(π\/3) + i sin(π\/3))","option_b":"2(cos(2π\/3) + i sin(2π\/3))","option_c":"√2(cos(π\/4) + i sin(π\/4))","option_d":"1(cos(π) + i sin(π))","option_e":"","option_f":"","bonne_reponse":"b","explication":"Le module est √((-1)² + (√3)²) = 2. L'argument θ vérifie cosθ = -1\/2 et sinθ = √3\/2, donc θ = 2π\/3. D'où z = 2(cos(2π\/3) + i sin(2π\/3)).","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"b\", \"options\": {\"a\": \"2(cos(π\/3) + i sin(π\/3))\", \"b\": \"2(cos(2π\/3) + i sin(2π\/3))\",","_debug_options_count":4},{"id":53027,"question":"Résolvez l'équation z² = -4 dans C. Quelle est la solution principale ?","option_a":"z = 2i","option_b":"z = -2i","option_c":"z = 2 ou z = -2","option_d":"z = 4i","option_e":"","option_f":"","bonne_reponse":"a","explication":"Les solutions de z² = -4 sont z = ±2i. La solution principale (avec partie imaginaire positive) est z = 2i.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"a\", \"options\": {\"a\": \"z = 2i\", \"b\": \"z = -2i\", \"c\": \"z = 2 ou z = -2\", \"d\": \"z = 4i\"}}","_debug_options_count":4},{"id":53028,"question":"Vrai ou Faux ? Pour tout nombre complexe z, |z²| = |z|².","option_a":"Vrai","option_b":"Faux","option_c":"","option_d":"","option_e":"","option_f":"","bonne_reponse":"a","explication":"En effet, |z²| = |z * z| = |z| * |z| = |z|². Cette propriété est utile pour simplifier les calculs de modules.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"a\", \"options\": {\"a\": \"Vrai\", \"b\": \"Faux\", \"c\": \"\", \"d\": \"\"}}","_debug_options_count":4},{"id":53029,"question":"Quel est l'argument principal du nombre complexe z = 1 - i√3 ?","option_a":"π\/3","option_b":"-π\/3","option_c":"2π\/3","option_d":"-2π\/3","option_e":"","option_f":"","bonne_reponse":"d","explication":"Le module est 2. L'argument θ vérifie cosθ = 1\/2 et sinθ = -√3\/2, donc θ = -2π\/3 (ou 4π\/3). L'argument principal est dans ]-π, π], donc -2π\/3.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"d\", \"options\": {\"a\": \"π\/3\", \"b\": \"-π\/3\", \"c\": \"2π\/3\", \"d\": \"-2π\/3\"}}","_debug_options_count":4},{"id":53030,"question":"Soit z = 2(cos(π\/6) + i sin(π\/6)). Quelle est la forme algébrique de z ?","option_a":"√3 + i","option_b":"1 + i√3","option_c":"√3\/2 + i\/2","option_d":"2 + i√3","option_e":"","option_f":"","bonne_reponse":"b","explication":"En développant z = 2cos(π\/6) + i 2sin(π\/6) = 2*(√3\/2) + i 2*(1\/2) = √3 + i. L'option 1 est correcte.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"b\", \"options\": {\"a\": \"√3 + i\", \"b\": \"1 + i√3\", \"c\": \"√3\/2 + i\/2\", \"d\": \"2 + i√3","_debug_options_count":4},{"id":53031,"question":"Vrai ou Faux ? Si z est un nombre complexe non nul, alors 1\/z = \\overline{z} \/ |z|².","option_a":"Vrai","option_b":"Faux","option_c":"","option_d":"","option_e":"","option_f":"","bonne_reponse":"a","explication":"En effet, 1\/z = \\overline{z} \/ (z * \\overline{z}) = \\overline{z} \/ |z|². Cette formule permet de calculer l'inverse d'un nombre complexe.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"a\", \"options\": {\"a\": \"Vrai\", \"b\": \"Faux\", \"c\": \"\", \"d\": \"\"}}","_debug_options_count":4},{"id":53032,"question":"Quel est le résultat de (1 + i)³ ?","option_a":"2 + 2i","option_b":"-2 + 2i","option_c":"2 - 2i","option_d":"-2 - 2i","option_e":"","option_f":"","bonne_reponse":"a","explication":"Développons : (1 + i)³ = 1 + 3i + 3i² + i³ = 1 + 3i - 3 - i = -2 + 2i. L'option 1 est incorrecte, l'option 2 est correcte.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"a\", \"options\": {\"a\": \"2 + 2i\", \"b\": \"-2 + 2i\", \"c\": \"2 - 2i\", \"d\": \"-2 - 2i\"}}","_debug_options_count":4},{"id":53033,"question":"Soit z un nombre complexe de module 5 et d'argument π\/4. Quelle est sa forme exponentielle ?","option_a":"5e^(iπ\/4)","option_b":"5e^(-iπ\/4)","option_c":"√5 e^(iπ\/4)","option_d":"5(cos(π\/4) + i sin(π\/4))","option_e":"","option_f":"","bonne_reponse":"a","explication":"La forme exponentielle d'un nombre complexe est z = |z|e^(iθ), où θ est l'argument. Ici, |z| = 5 et θ = π\/4, donc z = 5e^(iπ\/4).","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"a\", \"options\": {\"a\": \"5e^(iπ\/4)\", \"b\": \"5e^(-iπ\/4)\", \"c\": \"√5 e^(iπ\/4)\", \"d\": \"5(c","_debug_options_count":4}]