Quiz — 13 - Arcos - Arcsin 2.pdf

Question 1 sur 10 20:00

[{"id":54257,"question":"Quelle est la valeur principale de Arccos(1\/2) ?","option_a":"π\/6","option_b":"π\/3","option_c":"π\/4","option_d":"π\/2","option_e":"","option_f":"","bonne_reponse":"b","explication":"Arccos(1\/2) = π\/3 car cos(π\/3) = 1\/2 et π\/3 est dans l'intervalle [0, π] (domaine de définition de Arccos).","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"b\", \"options\": {\"a\": \"π\/6\", \"b\": \"π\/3\", \"c\": \"π\/4\", \"d\": \"π\/2\"}}","_debug_options_count":4},{"id":54258,"question":"La fonction Arcsin est-elle définie pour x = 2 ?","option_a":"Vrai","option_b":"Faux","option_c":"","option_d":"","option_e":"","option_f":"","bonne_reponse":"b","explication":"Faux. Le domaine de définition de Arcsin est [-1, 1]. Pour x = 2, la fonction n'est pas définie.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"b\", \"options\": {\"a\": \"Vrai\", \"b\": \"Faux\", \"c\": \"\", \"d\": \"\"}}","_debug_options_count":4},{"id":54259,"question":"Quelle est la dérivée de f(x) = Arccos(3x) ?","option_a":"-3 \/ sqrt(1 - 9x²)","option_b":"-1 \/ sqrt(1 - 9x²)","option_c":"3 \/ sqrt(1 - 9x²)","option_d":"1 \/ sqrt(1 - 9x²)","option_e":"","option_f":"","bonne_reponse":"a","explication":"En utilisant la règle de dérivation des fonctions composées, f'(x) = -3 \/ sqrt(1 - (3x)²) = -3 \/ sqrt(1 - 9x²).","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"a\", \"options\": {\"a\": \"-3 \/ sqrt(1 - 9x²)\", \"b\": \"-1 \/ sqrt(1 - 9x²)\", \"c\": \"3 \/ sqrt(","_debug_options_count":4},{"id":54260,"question":"L'équation Arcsin(x) = π\/4 a-t-elle une solution ?","option_a":"Vrai","option_b":"Faux","option_c":"","option_d":"","option_e":"","option_f":"","bonne_reponse":"b","explication":"Faux. L'image de Arcsin est [-π\/2, π\/2]. π\/4 est dans cet intervalle, mais Arcsin(x) = π\/4 implique x = sin(π\/4) = √2\/2, donc l'équation a une solution.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"b\", \"options\": {\"a\": \"Vrai\", \"b\": \"Faux\", \"c\": \"\", \"d\": \"\"}}","_debug_options_count":4},{"id":54261,"question":"Quelle est la valeur de sin(Arcsin(0.5)) ?","option_a":"0.5","option_b":"π\/6","option_c":"1","option_d":"0","option_e":"","option_f":"","bonne_reponse":"a","explication":"Par définition, sin(Arcsin(x)) = x pour tout x dans [-1, 1]. Donc sin(Arcsin(0.5)) = 0.5.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"a\", \"options\": {\"a\": \"0.5\", \"b\": \"π\/6\", \"c\": \"1\", \"d\": \"0\"}}","_debug_options_count":4},{"id":54262,"question":"La fonction Arccos est-elle paire ?","option_a":"Vrai","option_b":"Faux","option_c":"","option_d":"","option_e":"","option_f":"","bonne_reponse":"b","explication":"Faux. Une fonction paire vérifie f(-x) = f(x). Or, Arccos(-x) = π - Arccos(x), donc Arccos n'est pas paire.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"b\", \"options\": {\"a\": \"Vrai\", \"b\": \"Faux\", \"c\": \"\", \"d\": \"\"}}","_debug_options_count":4},{"id":54263,"question":"Résolvez l'équation : 2Arccos(x) = π.","option_a":"x = 0","option_b":"x = 1","option_c":"x = -1","option_d":"x = 1\/2","option_e":"","option_f":"","bonne_reponse":"b","explication":"En divisant par 2, on obtient Arccos(x) = π\/2. Or, Arccos(0) = π\/2, donc x = 0. Attention, la solution est x = 0, pas x = 1.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"b\", \"options\": {\"a\": \"x = 0\", \"b\": \"x = 1\", \"c\": \"x = -1\", \"d\": \"x = 1\/2\"}}","_debug_options_count":4},{"id":54264,"question":"Quelle est la dérivée de g(x) = Arcsin(x²) ?","option_a":"2x \/ sqrt(1 - x⁴)","option_b":"x \/ sqrt(1 - x²)","option_c":"2x \/ sqrt(1 - x²)","option_d":"1 \/ sqrt(1 - x⁴)","option_e":"","option_f":"","bonne_reponse":"a","explication":"En utilisant la règle de dérivation des fonctions composées, g'(x) = (2x) \/ sqrt(1 - (x²)²) = 2x \/ sqrt(1 - x⁴).","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"a\", \"options\": {\"a\": \"2x \/ sqrt(1 - x⁴)\", \"b\": \"x \/ sqrt(1 - x²)\", \"c\": \"2x \/ sqrt(1","_debug_options_count":4},{"id":54265,"question":"L'équation Arccos(x) = Arcsin(x) a-t-elle une solution ?","option_a":"Vrai","option_b":"Faux","option_c":"","option_d":"","option_e":"","option_f":"","bonne_reponse":"b","explication":"Vrai. En posant θ = Arccos(x), on a cos(θ) = x et sin(θ) = x. Or, sin²(θ) + cos²(θ) = 1, donc 2x² = 1 ⇒ x = ±√2\/2. Seule x = √2\/2 est dans le domaine de définition.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"b\", \"options\": {\"a\": \"Vrai\", \"b\": \"Faux\", \"c\": \"\", \"d\": \"\"}}","_debug_options_count":4},{"id":54266,"question":"Quelle est la valeur de cos(Arcsin(3\/5)) ?","option_a":"3\/5","option_b":"4\/5","option_c":"5\/13","option_d":"12\/13","option_e":"","option_f":"","bonne_reponse":"b","explication":"Soit θ = Arcsin(3\/5). Alors sin(θ) = 3\/5. En utilisant l'identité sin²(θ) + cos²(θ) = 1, on trouve cos(θ) = 4\/5 (car θ est dans [-π\/2, π\/2] où cos est positif).","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"b\", \"options\": {\"a\": \"3\/5\", \"b\": \"4\/5\", \"c\": \"5\/13\", \"d\": \"12\/13\"}}","_debug_options_count":4}]