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Question 1 sur 10 10:00

[{"id":25748,"question":"Quelle est la limite de la fonction f(x) = (x² - 1)\/(x - 1) lorsque x tend vers 1 ?","option_a":"A. 0","option_b":"B. 1","option_c":"C. 2","option_d":"D. La limite n'existe pas","option_e":"","option_f":"","bonne_reponse":"C","explication":"En factorisant le numérateur, on obtient f(x) = (x+1)(x-1)\/(x-1) = x+1 pour x ≠ 1. Ainsi, la limite est 2.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0},{"id":25749,"question":"La fonction f(x) = x³ - 3x est croissante sur l'intervalle [-1, 1].","option_a":"Vrai","option_b":"Faux","option_c":"","option_d":"","option_e":"","option_f":"","bonne_reponse":"A","explication":"La dérivée f'(x) = 3x² - 3 est négative sur [-1, 1], donc la fonction est décroissante sur cet intervalle.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0},{"id":25750,"question":"Quelle est la solution de l'équation ln(x) + ln(2) = 0 ?","option_a":"A. x = 1\/2","option_b":"B. x = 1","option_c":"C. x = 2","option_d":"D. x = e","option_e":"","option_f":"","bonne_reponse":"A","explication":"L'équation se réécrit ln(2x) = 0, donc 2x = 1, soit x = 1\/2.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0},{"id":25751,"question":"Le vecteur u(2, -1, 3) et v(-1, 2, 0) sont orthogonaux.","option_a":"Vrai","option_b":"Faux","option_c":"","option_d":"","option_e":"","option_f":"","bonne_reponse":"B","explication":"Le produit scalaire u·v = 2*(-1) + (-1)*2 + 3*0 = -4 ≠ 0, donc les vecteurs ne sont pas orthogonaux.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0},{"id":25752,"question":"Quelle est la dérivée de la fonction f(x) = e^(2x+1) ?","option_a":"A. f'(x) = e^(2x+1)","option_b":"B. f'(x) = 2e^(2x+1)","option_c":"C. f'(x) = (2x+1)e^(2x)","option_d":"D. f'(x) = 2xe^(2x+1)","option_e":"","option_f":"","bonne_reponse":"B","explication":"En appliquant la règle de dérivation des fonctions exponentielles, f'(x) = 2e^(2x+1).","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0},{"id":25753,"question":"La suite définie par uₙ = n²\/(n+1) est convergente.","option_a":"Vrai","option_b":"Faux","option_c":"","option_d":"","option_e":"","option_f":"","bonne_reponse":"A","explication":"La suite diverge vers +∞ car le terme dominant est n²\/(n) = n.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0},{"id":25754,"question":"Quelle est l'intégrale ∫(3x² + 2x + 1) dx ?","option_a":"A. x³ + x² + x + C","option_b":"B. x³ + x² + C","option_c":"C. 3x³ + 2x² + x + C","option_d":"D. x³ + x + C","option_e":"","option_f":"","bonne_reponse":"A","explication":"L'intégrale se calcule terme à terme : ∫3x² dx = x³, ∫2x dx = x², ∫1 dx = x, donc la réponse est x³ + x² + x + C.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0},{"id":25755,"question":"Le plan d'équation x + 2y - z = 5 passe par le point A(1, 2, 0).","option_a":"Vrai","option_b":"Faux","option_c":"","option_d":"","option_e":"","option_f":"","bonne_reponse":"B","explication":"En substituant les coordonnées de A dans l'équation, on obtient 1 + 4 - 0 = 5, ce qui est vrai. Donc le point appartient au plan.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0},{"id":25756,"question":"Quelle est la solution de l'inéquation 2^(x+1) ≥ 8 ?","option_a":"A. x ≥ 1","option_b":"B. x ≥ 2","option_c":"C. x ≥ 3","option_d":"D. x ≥ 0","option_e":"","option_f":"","bonne_reponse":"C","explication":"L'inéquation se réécrit 2^(x+1) ≥ 2³, donc x+1 ≥ 3, soit x ≥ 2. Cependant, 2^(x+1) ≥ 8 implique x+1 ≥ 3, donc x ≥ 2. Mais 2^3 = 8, donc x ≥ 2 est correct.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0},{"id":25757,"question":"La fonction f(x) = x\/(x²+1) est bornée sur ℝ.","option_a":"Vrai","option_b":"Faux","option_c":"","option_d":"","option_e":"","option_f":"","bonne_reponse":"A","explication":"La fonction atteint son maximum en x=1 (f(1)=1\/2) et son minimum en x=-1 (f(-1)=-1\/2), donc elle est bornée.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0}]