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Question 1 sur 5 10:00

[{"id":2649,"question":"Quelle est la solution de l'équation 2x² - 5x + 2 = 0 ?","option_a":"x = 1 ou x = 2","option_b":"x = 0.5 ou x = 2","option_c":"x = -1 ou x = -2","option_d":"x = 1 ou x = -2","option_e":"","option_f":"","bonne_reponse":"B","explication":"L'équation se résout en utilisant la formule du discriminant Δ = b² - 4ac. Ici, Δ = 25 - 16 = 9, donc les solutions sont x = (5 ± 3)\/4.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0},{"id":2650,"question":"Si f(x) = 3x + 2, quelle est la valeur de f(4) ?","option_a":"10","option_b":"14","option_c":"12","option_d":"16","option_e":"","option_f":"","bonne_reponse":"C","explication":"Il suffit de remplacer x par 4 dans l'expression de la fonction : f(4) = 3*4 + 2 = 14.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0},{"id":2651,"question":"Quelle est la limite de (x² - 4)\/(x - 2) lorsque x tend vers 2 ?","option_a":"0","option_b":"4","option_c":"indéterminée","option_d":"2","option_e":"","option_f":"","bonne_reponse":"B","explication":"Factorisons le numérateur : (x² - 4) = (x - 2)(x + 2). La limite devient (x + 2) lorsque x tend vers 2, soit 4.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0},{"id":2652,"question":"Résolvez l'inéquation 3x - 7 ≤ 5x + 1.","option_a":"x ≥ -4","option_b":"x ≤ -4","option_c":"x ≥ 4","option_d":"x ≤ 4","option_e":"","option_f":"","bonne_reponse":"A","explication":"En isolant x : -7 - 1 ≤ 5x - 3x → -8 ≤ 2x → x ≥ -4.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0},{"id":2653,"question":"Quelle est la dérivée de la fonction f(x) = x³ - 2x² + x ?","option_a":"3x² - 4x + 1","option_b":"x² - 2x","option_c":"3x² - 4x","option_d":"x³ - 4x + 1","option_e":"","option_f":"","bonne_reponse":"A","explication":"La dérivée se calcule terme par terme : f'(x) = 3x² - 4x + 1.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0}]