Quiz — Serie Physique 24.01.2022 RLC Forcées.pdf

Question 1 sur 10 20:00

[{"id":36520,"question":"Dans un circuit RLC série, l'impédance totale Z est donnée par :","option_a":"Z = R + Lω + 1\/(Cω)","option_b":"Z = √(R² + (Lω - 1\/(Cω))²)","option_c":"Z = R² + (Lω - 1\/(Cω))²","option_d":"Z = R\/(Lω - 1\/(Cω))","option_e":"","option_f":"","bonne_reponse":"b","explication":"L'impédance complexe d'un circuit RLC série est Z = R + j(Lω - 1\/(Cω)), donc son module est Z = √(R² + (Lω - 1\/(Cω))²).","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"b\", \"options\": {\"a\": \"Z = R + Lω + 1\/(Cω)\", \"b\": \"Z = √(R² + (Lω - 1\/(Cω))²)\", ","_debug_options_count":4},{"id":36521,"question":"La fréquence de résonance d'un circuit RLC série est indépendante de la résistance R.","option_a":"Vrai","option_b":"Faux","option_c":"","option_d":"","option_e":"","option_f":"","bonne_reponse":"a","explication":"La fréquence de résonance f₀ = 1\/(2π√(LC)) ne dépend que de L et C, pas de R. La résistance influence l'amortissement mais pas la fréquence de résonance.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"a\", \"options\": {\"a\": \"Vrai\", \"b\": \"Faux\", \"c\": \"\", \"d\": \"\"}}","_debug_options_count":4},{"id":36522,"question":"À la résonance, dans un circuit RLC série, le courant est :","option_a":"En avance de phase par rapport à la tension","option_b":"En retard de phase par rapport à la tension","option_c":"En phase avec la tension","option_d":"Déphasé de 90° par rapport à la tension","option_e":"","option_f":"","bonne_reponse":"c","explication":"À la résonance, l'impédance est purement résistive (Lω = 1\/(Cω)), donc le courant et la tension sont en phase.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"c\", \"options\": {\"a\": \"En avance de phase par rapport à la tension\", \"b\": \"En retard de","_debug_options_count":4},{"id":36523,"question":"Le facteur de qualité Q d'un circuit RLC série est défini par :","option_a":"Q = R√(C\/L)","option_b":"Q = 1\/(R√(L\/C))","option_c":"Q = √(L\/C)\/R","option_d":"Q = R\/(√(L\/C))","option_e":"","option_f":"","bonne_reponse":"c","explication":"Le facteur de qualité est Q = (1\/R)√(L\/C) = ω₀L\/R, où ω₀ est la pulsation de résonance.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"c\", \"options\": {\"a\": \"Q = R√(C\/L)\", \"b\": \"Q = 1\/(R√(L\/C))\", \"c\": \"Q = √(L\/C)\/R\", ","_debug_options_count":4},{"id":36524,"question":"Pour un circuit RLC série, si on augmente la capacité C, la fréquence de résonance :","option_a":"Augmente","option_b":"Diminue","option_c":"Reste inchangée","option_d":"Devient nulle","option_e":"","option_f":"","bonne_reponse":"b","explication":"La fréquence de résonance f₀ = 1\/(2π√(LC)) diminue lorsque C augmente, car √(LC) augmente.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"b\", \"options\": {\"a\": \"Augmente\", \"b\": \"Diminue\", \"c\": \"Reste inchangée\", \"d\": \"Devient","_debug_options_count":4},{"id":36525,"question":"Le déphasage φ entre la tension et le courant dans un circuit RLC série est donné par :","option_a":"tan(φ) = R\/(Lω - 1\/(Cω))","option_b":"tan(φ) = (Lω - 1\/(Cω))\/R","option_c":"tan(φ) = R(Lω - 1\/(Cω))","option_d":"tan(φ) = (Lω + 1\/(Cω))\/R","option_e":"","option_f":"","bonne_reponse":"b","explication":"Le déphasage φ vérifie tan(φ) = (Lω - 1\/(Cω))\/R, où Lω - 1\/(Cω) est la réactance totale.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"b\", \"options\": {\"a\": \"tan(φ) = R\/(Lω - 1\/(Cω))\", \"b\": \"tan(φ) = (Lω - 1\/(Cω))\/R\",","_debug_options_count":4},{"id":36526,"question":"Dans un circuit RLC parallèle, à la résonance, l'impédance est :","option_a":"Vrai","option_b":"Faux","option_c":"","option_d":"","option_e":"","option_f":"","bonne_reponse":"b","explication":"Faux. Dans un circuit RLC parallèle, à la résonance, l'impédance est maximale (et non minimale comme dans le cas série).","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"b\", \"options\": {\"a\": \"Vrai\", \"b\": \"Faux\", \"c\": \"\", \"d\": \"\"}}","_debug_options_count":4},{"id":36527,"question":"La puissance active dissipée dans un circuit RLC série est maximale :","option_a":"À la résonance","option_b":"Pour une fréquence nulle","option_c":"Pour une fréquence infinie","option_d":"Lorsque Lω = 0","option_e":"","option_f":"","bonne_reponse":"a","explication":"La puissance active P = RI² est maximale lorsque le courant I est maximal, ce qui se produit à la résonance.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"a\", \"options\": {\"a\": \"À la résonance\", \"b\": \"Pour une fréquence nulle\", \"c\": \"Pour u","_debug_options_count":4},{"id":36528,"question":"Le facteur de qualité Q d'un circuit RLC parallèle est donné par :","option_a":"Q = R√(C\/L)","option_b":"Q = 1\/(R√(L\/C))","option_c":"Q = √(L\/C)\/R","option_d":"Q = R\/(√(L\/C))","option_e":"","option_f":"","bonne_reponse":"a","explication":"Pour un circuit RLC parallèle, le facteur de qualité est Q = R√(C\/L), car l'impédance est maximale à la résonance.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"a\", \"options\": {\"a\": \"Q = R√(C\/L)\", \"b\": \"Q = 1\/(R√(L\/C))\", \"c\": \"Q = √(L\/C)\/R\", ","_debug_options_count":4},{"id":36529,"question":"Si on double la fréquence d'excitation d'un circuit RLC série initialement à la résonance, l'impédance :","option_a":"Diminue","option_b":"Augmente","option_c":"Reste la même","option_d":"Devient nulle","option_e":"","option_f":"","bonne_reponse":"b","explication":"Si on double la fréquence, Lω augmente et 1\/(Cω) diminue, donc la réactance totale (Lω - 1\/(Cω)) augmente, ce qui augmente l'impédance Z.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"b\", \"options\": {\"a\": \"Diminue\", \"b\": \"Augmente\", \"c\": \"Reste la même\", \"d\": \"Devient n","_debug_options_count":4}]