Série d'exercices corrigés pour maîtriser les nombres complexes en Terminale Maths. Préparation Bac et révisions efficaces.
Question 1 sur 10 10:00
[{"id":64942,"question":"Quel est le module du nombre complexe z = 3 - 4i ?","option_a":"5","option_b":"7","option_c":"1","option_d":"√7","option_e":"","option_f":"","bonne_reponse":"A","explication":"Le module se calcule par |z| = √(3² + (-4)²) = √(9 + 16) = √25 = 5.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0},{"id":64943,"question":"L'argument d'un nombre complexe est toujours un angle en degrés.","option_a":"Vrai","option_b":"Faux","option_c":"","option_d":"","option_e":"","option_f":"","bonne_reponse":"B","explication":"L'argument peut s'exprimer en radians ou en degrés, selon le contexte.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0},{"id":64944,"question":"Quelle est la forme trigonométrique de z = 1 + i ?","option_a":"√2(cos(π\/4) + i sin(π\/4))","option_b":"2(cos(π\/4) + i sin(π\/4))","option_c":"√2(cos(π\/2) + i sin(π\/2))","option_d":"1(cos(π\/4) + i sin(π\/4))","option_e":"","option_f":"","bonne_reponse":"A","explication":"Le module est √(1² + 1²) = √2 et l'argument est π\/4, d'où la forme √2(cos(π\/4) + i sin(π\/4)).","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0},{"id":64945,"question":"Le produit de deux nombres complexes a pour module la somme de leurs modules.","option_a":"Vrai","option_b":"Faux","option_c":"","option_d":"","option_e":"","option_f":"","bonne_reponse":"B","explication":"Le module du produit est le produit des modules, pas la somme.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0},{"id":64946,"question":"Quel est le conjugué du nombre complexe z = 2 + 3i ?","option_a":"2 - 3i","option_b":"-2 + 3i","option_c":"3 + 2i","option_d":"2 + 3i","option_e":"","option_f":"","bonne_reponse":"A","explication":"Le conjugué d'un nombre complexe z = a + bi est z̄ = a - bi.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0},{"id":64947,"question":"La formule d'Euler lie les nombres complexes à la trigonométrie.","option_a":"Vrai","option_b":"Faux","option_c":"","option_d":"","option_e":"","option_f":"","bonne_reponse":"A","explication":"La formule d'Euler est e^(iθ) = cos(θ) + i sin(θ), reliant exponentielles et fonctions trigonométriques.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0},{"id":64948,"question":"Résoudre l'équation z² = -1 dans ℂ donne :","option_a":"z = i","option_b":"z = -i","option_c":"z = i ou z = -i","option_d":"Aucune solution","option_e":"","option_f":"","bonne_reponse":"C","explication":"Les solutions sont z = i et z = -i, car i² = -1 et (-i)² = -1.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0},{"id":64949,"question":"Le nombre complexe z = 5(cos(π\/3) + i sin(π\/3)) a pour forme algébrique :","option_a":"5\/2 + 5√3\/2 i","option_b":"5√3\/2 + 5\/2 i","option_c":"5 + 5√3 i","option_d":"√3\/2 + 1\/2 i","option_e":"","option_f":"","bonne_reponse":"A","explication":"En développant : 5(cos(π\/3) + i sin(π\/3)) = 5(1\/2 + i √3\/2) = 5\/2 + 5√3\/2 i.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0},{"id":64950,"question":"L'inverse d'un nombre complexe non nul z = a + bi est donné par 1\/z = (a - bi)\/(a² + b²).","option_a":"Vrai","option_b":"Faux","option_c":"","option_d":"","option_e":"","option_f":"","bonne_reponse":"A","explication":"L'inverse de z = a + bi est z̄\/|z|² = (a - bi)\/(a² + b²).","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0},{"id":64951,"question":"Quel est l'argument principal du nombre complexe z = -1 - i ?","option_a":"3π\/4","option_b":"-3π\/4","option_c":"5π\/4","option_d":"-π\/4","option_e":"","option_f":"","bonne_reponse":"B","explication":"Dans le plan complexe, z = -1 - i est dans le 3ème quadrant. Son argument principal est -3π\/4 (ou 5π\/4 en positif).","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0}]
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