Quiz — Serie d'exercices (Lycée pilote) - Math - Les fonctions (3) - 2ème Sciences.pdf
🧠 Quiz 10 questions 20 min
QUIZ INTERACTIFDiff. 5/10
Quiz interactif généré par IA à partir du document : Serie d'exercices (Lycée pilote) - Math - Les fonctions (3) - 2ème Sciences.pdf
Question 1 sur 10 20:00
[{"id":27870,"question":"Quelle est l'image de -2 par la fonction f définie par f(x) = 3x² + 2x - 1 ?","option_a":"15","option_b":"13","option_c":"11","option_d":"9","option_e":"","option_f":"","bonne_reponse":"a","explication":"Calculer f(-2) = 3*(-2)² + 2*(-2) - 1 = 12 - 4 - 1 = 7. L'image de -2 est donc 7.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"a\", \"options\": {\"a\": \"15\", \"b\": \"13\", \"c\": \"11\", \"d\": \"9\"}}","_debug_options_count":4},{"id":27871,"question":"Une fonction paire est toujours symétrique par rapport à l'axe des ordonnées.","option_a":"Vrai","option_b":"Faux","option_c":"","option_d":"","option_e":"","option_f":"","bonne_reponse":"a","explication":"Par définition, une fonction f est paire si f(-x) = f(x) pour tout x du domaine, ce qui implique une symétrie par rapport à l'axe des ordonnées.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"a\", \"options\": {\"a\": \"Vrai\", \"b\": \"Faux\", \"c\": \"\", \"d\": \"\"}}","_debug_options_count":4},{"id":27872,"question":"Quelle est la solution de l'équation f(x) = 0 pour la fonction f(x) = x² - 5x + 6 ?","option_a":"x = 2 ou x = 3","option_b":"x = -2 ou x = -3","option_c":"x = 1 ou x = 6","option_d":"x = 0 ou x = 5","option_e":"","option_f":"","bonne_reponse":"a","explication":"Résoudre x² - 5x + 6 = 0 : le discriminant est Δ = 25 - 24 = 1, donc x = (5 ± 1)\/2. Les solutions sont x = 2 et x = 3.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"a\", \"options\": {\"a\": \"x = 2 ou x = 3\", \"b\": \"x = -2 ou x = -3\", \"c\": \"x = 1 ou x = 6\", ","_debug_options_count":4},{"id":27873,"question":"La fonction f(x) = 1\/x est définie pour x = 0.","option_a":"Vrai","option_b":"Faux","option_c":"","option_d":"","option_e":"","option_f":"","bonne_reponse":"b","explication":"La fonction f(x) = 1\/x n'est pas définie en x = 0 car la division par zéro est impossible.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"b\", \"options\": {\"a\": \"Vrai\", \"b\": \"Faux\", \"c\": \"\", \"d\": \"\"}}","_debug_options_count":4},{"id":27874,"question":"Quelle est la dérivée de la fonction f(x) = 4x³ - 2x² + x - 5 ?","option_a":"f'(x) = 12x² - 4x + 1","option_b":"f'(x) = 12x² - 4x","option_c":"f'(x) = 4x² - 2x + 1","option_d":"f'(x) = 12x - 4","option_e":"","option_f":"","bonne_reponse":"a","explication":"La dérivée de f(x) = 4x³ - 2x² + x - 5 est f'(x) = 12x² - 4x + 1 (dérivée terme à terme).","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"a\", \"options\": {\"a\": \"f'(x) = 12x² - 4x + 1\", \"b\": \"f'(x) = 12x² - 4x\", \"c\": \"f'(x) =","_debug_options_count":4},{"id":27875,"question":"Une fonction strictement croissante sur ℝ peut avoir un minimum local.","option_a":"Vrai","option_b":"Faux","option_c":"","option_d":"","option_e":"","option_f":"","bonne_reponse":"b","explication":"Une fonction strictement croissante sur ℝ ne peut pas avoir de minimum local car elle est toujours croissante.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"b\", \"options\": {\"a\": \"Vrai\", \"b\": \"Faux\", \"c\": \"\", \"d\": \"\"}}","_debug_options_count":4},{"id":27876,"question":"Quelle est l'équation de la tangente à la courbe de f(x) = x² au point d'abscisse x = 1 ?","option_a":"y = 2x - 1","option_b":"y = x + 1","option_c":"y = 2x + 1","option_d":"y = x - 1","option_e":"","option_f":"","bonne_reponse":"a","explication":"La tangente a pour équation y = f'(a)(x - a) + f(a). Ici, f'(x) = 2x, donc f'(1) = 2 et f(1) = 1. L'équation est y = 2(x - 1) + 1 = 2x - 1.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"a\", \"options\": {\"a\": \"y = 2x - 1\", \"b\": \"y = x + 1\", \"c\": \"y = 2x + 1\", \"d\": \"y = x - 1","_debug_options_count":4},{"id":27877,"question":"La fonction f(x) = √x est définie pour tout x réel.","option_a":"Vrai","option_b":"Faux","option_c":"","option_d":"","option_e":"","option_f":"","bonne_reponse":"b","explication":"La fonction f(x) = √x n'est définie que pour x ≥ 0, car la racine carrée d'un nombre négatif n'existe pas dans ℝ.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"b\", \"options\": {\"a\": \"Vrai\", \"b\": \"Faux\", \"c\": \"\", \"d\": \"\"}}","_debug_options_count":4},{"id":27878,"question":"Quelle est la limite de la fonction f(x) = (3x² + 2x - 1)\/(x² - 4) lorsque x tend vers +∞ ?","option_a":"3","option_b":"2","option_c":"1","option_d":"∞","option_e":"","option_f":"","bonne_reponse":"a","explication":"En divisant numérateur et dénominateur par x², on obtient (3 + 2\/x - 1\/x²)\/(1 - 4\/x²). Lorsque x → +∞, les termes en 1\/x tendent vers 0, donc la limite est 3\/1 = 3.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"a\", \"options\": {\"a\": \"3\", \"b\": \"2\", \"c\": \"1\", \"d\": \"∞\"}}","_debug_options_count":4},{"id":27879,"question":"Une fonction constante est toujours paire.","option_a":"Vrai","option_b":"Faux","option_c":"","option_d":"","option_e":"","option_f":"","bonne_reponse":"a","explication":"Une fonction constante f(x) = k vérifie f(-x) = k = f(x) pour tout x, donc elle est paire.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"a\", \"options\": {\"a\": \"Vrai\", \"b\": \"Faux\", \"c\": \"\", \"d\": \"\"}}","_debug_options_count":4}]
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