Quiz — 64566324de25d_corrigé_serie-radioactivite (1).pdf

Question 1 sur 10 20:00

[{"id":83082,"question":"Quel type de rayonnement est constitué de noyaux d'hélium ?","option_a":"Rayonnement alpha (α)","option_b":"Rayonnement bêta (β)","option_c":"Rayonnement gamma (γ)","option_d":"Rayons X","option_e":"","option_f":"","bonne_reponse":"a","explication":"Le rayonnement alpha (α) est composé de noyaux d'hélium (2 protons et 2 neutrons), émis lors de la désintégration de certains noyaux lourds.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"a\", \"options\": {\"a\": \"Rayonnement alpha (α)\", \"b\": \"Rayonnement bêta (β)\", \"c\": \"Ray","_debug_options_count":4},{"id":83083,"question":"La demi-vie d'un isotope radioactif est toujours constante.","option_a":"Vrai","option_b":"Faux","option_c":"","option_d":"","option_e":"","option_f":"","bonne_reponse":"a","explication":"La demi-vie est une caractéristique intrinsèque du noyau radioactif et reste constante, indépendamment des conditions extérieures.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"a\", \"options\": {\"a\": \"Vrai\", \"b\": \"Faux\", \"c\": \"\", \"d\": \"\"}}","_debug_options_count":4},{"id":83084,"question":"Quelle est l'unité d'activité radioactive dans le système international ?","option_a":"Curie (Ci)","option_b":"Becquerel (Bq)","option_c":"Gray (Gy)","option_d":"Sievert (Sv)","option_e":"","option_f":"","bonne_reponse":"b","explication":"Le Becquerel (Bq) est l'unité SI de l'activité radioactive, définie comme une désintégration par seconde.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"b\", \"options\": {\"a\": \"Curie (Ci)\", \"b\": \"Becquerel (Bq)\", \"c\": \"Gray (Gy)\", \"d\": \"Sieve","_debug_options_count":4},{"id":83085,"question":"Lors d'une désintégration bêta moins (β⁻), un neutron se transforme en :","option_a":"Un proton","option_b":"Un électron","option_c":"Un positron","option_d":"Un photon","option_e":"","option_f":"","bonne_reponse":"a","explication":"Lors d'une désintégration β⁻, un neutron se transforme en un proton, avec émission d'un électron (particule β⁻) et d'un antineutrino.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"a\", \"options\": {\"a\": \"Un proton\", \"b\": \"Un électron\", \"c\": \"Un positron\", \"d\": \"Un pho","_debug_options_count":4},{"id":83086,"question":"Le rayonnement gamma (γ) est de nature :","option_a":"Vrai","option_b":"Faux","option_c":"","option_d":"","option_e":"","option_f":"","bonne_reponse":"a","explication":"Le rayonnement gamma (γ) est un rayonnement électromagnétique de haute énergie, sans masse ni charge, émis lors de la désexcitation d'un noyau.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"a\", \"options\": {\"a\": \"Vrai\", \"b\": \"Faux\", \"c\": \"\", \"d\": \"\"}}","_debug_options_count":4},{"id":83087,"question":"Quelle loi permet de calculer le nombre de noyaux restants après un temps t ?","option_a":"Loi de Beer-Lambert","option_b":"Loi de décroissance radioactive","option_c":"Loi des gaz parfaits","option_d":"Loi d'Ohm","option_e":"","option_f":"","bonne_reponse":"b","explication":"La loi de décroissance radioactive N(t) = N₀e^(-λt) permet de calculer le nombre de noyaux restants après un temps t, où λ est la constante radioactive.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"b\", \"options\": {\"a\": \"Loi de Beer-Lambert\", \"b\": \"Loi de décroissance radioactive\", \"c","_debug_options_count":4},{"id":83088,"question":"Un échantillon de 1000 noyaux radioactifs a une demi-vie de 5 ans. Combien de noyaux resteront après 10 ans ?","option_a":"250","option_b":"500","option_c":"750","option_d":"1000","option_e":"","option_f":"","bonne_reponse":"a","explication":"Après 10 ans (2 demi-vies), il reste 1000 × (1\/2)^2 = 250 noyaux.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"a\", \"options\": {\"a\": \"250\", \"b\": \"500\", \"c\": \"750\", \"d\": \"1000\"}}","_debug_options_count":4},{"id":83089,"question":"Le rayonnement bêta plus (β⁺) est associé à l'émission d'un :","option_a":"Électron","option_b":"Positron","option_c":"Proton","option_d":"Neutron","option_e":"","option_f":"","bonne_reponse":"b","explication":"Le rayonnement β⁺ correspond à l'émission d'un positron (anti-électron) lors de la transformation d'un proton en neutron.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"b\", \"options\": {\"a\": \"Électron\", \"b\": \"Positron\", \"c\": \"Proton\", \"d\": \"Neutron\"}}","_debug_options_count":4},{"id":83090,"question":"La constante radioactive λ est liée à la demi-vie T par la relation :","option_a":"Vrai","option_b":"Faux","option_c":"","option_d":"","option_e":"","option_f":"","bonne_reponse":"a","explication":"La relation est λ = ln(2)\/T, où T est la demi-vie du noyau radioactif.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"a\", \"options\": {\"a\": \"Vrai\", \"b\": \"Faux\", \"c\": \"\", \"d\": \"\"}}","_debug_options_count":4},{"id":83091,"question":"Quel est l'effet principal des rayonnements ionisants sur la matière ?","option_a":"Chauffage","option_b":"Ionisation des atomes","option_c":"Magnétisation","option_d":"Expansion thermique","option_e":"","option_f":"","bonne_reponse":"b","explication":"Les rayonnements ionisants (α, β, γ) provoquent l'ionisation des atomes en arrachant des électrons, ce qui peut endommager les molécules biologiques.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0,"_debug_answer_data_type":"string","_debug_answer_data_preview":"{\"correct\": \"b\", \"options\": {\"a\": \"Chauffage\", \"b\": \"Ionisation des atomes\", \"c\": \"Magnétisation\", ","_debug_options_count":4}]