Maîtrisez les équations et fonctions en 4ème année secondaire

Question 1 sur 10 10:00

[{"id":72132,"question":"Quelle est la solution de l'équation 3x - 5 = 10 ?","option_a":"x = 5","option_b":"x = 15\/3","option_c":"x = 5\/3","option_d":"x = 15","option_e":"","option_f":"","bonne_reponse":"A","explication":"Pour résoudre 3x - 5 = 10, on ajoute 5 des deux côtés : 3x = 15, puis on divise par 3 : x = 5.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0},{"id":72133,"question":"La fonction f(x) = 2x + 3 est une fonction affine.","option_a":"Vrai","option_b":"Faux","option_c":"","option_d":"","option_e":"","option_f":"","bonne_reponse":"A","explication":"Une fonction affine s'écrit sous la forme f(x) = ax + b, ce qui est le cas ici avec a = 2 et b = 3.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0},{"id":72134,"question":"Quelle est la solution de l'équation x² - 5x + 6 = 0 ?","option_a":"x = 2 ou x = 3","option_b":"x = -2 ou x = -3","option_c":"x = 1 ou x = 6","option_d":"x = 5","option_e":"","option_f":"","bonne_reponse":"A","explication":"En factorisant, on obtient (x - 2)(x - 3) = 0, donc les solutions sont x = 2 et x = 3.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0},{"id":72135,"question":"La fonction f(x) = -4x est une fonction linéaire.","option_a":"Vrai","option_b":"Faux","option_c":"","option_d":"","option_e":"","option_f":"","bonne_reponse":"A","explication":"Une fonction linéaire s'écrit sous la forme f(x) = ax, ce qui est le cas ici avec a = -4.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0},{"id":72136,"question":"Quelle est la solution de l'équation 2(x + 3) = 4x - 6 ?","option_a":"x = 6","option_b":"x = 0","option_c":"x = 3","option_d":"x = -3","option_e":"","option_f":"","bonne_reponse":"B","explication":"En développant, on obtient 2x + 6 = 4x - 6. On soustrait 2x : 6 = 2x - 6, puis on ajoute 6 : 12 = 2x. Enfin, on divise par 2 : x = 6.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0},{"id":72137,"question":"La fonction f(x) = x² + 2x + 1 est une fonction affine.","option_a":"Vrai","option_b":"Faux","option_c":"","option_d":"","option_e":"","option_f":"","bonne_reponse":"B","explication":"Une fonction affine doit être de degré 1. Ici, f(x) = x² + 2x + 1 est une fonction du second degré.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0},{"id":72138,"question":"Quelle est la solution de l'équation 5x + 7 = 2x - 8 ?","option_a":"x = -5","option_b":"x = 5","option_c":"x = -15\/3","option_d":"x = 15","option_e":"","option_f":"","bonne_reponse":"A","explication":"On soustrait 2x : 3x + 7 = -8, puis on soustrait 7 : 3x = -15. Enfin, on divise par 3 : x = -5.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0},{"id":72139,"question":"La fonction f(x) = 7 est une fonction constante.","option_a":"Vrai","option_b":"Faux","option_c":"","option_d":"","option_e":"","option_f":"","bonne_reponse":"A","explication":"Une fonction constante est de la forme f(x) = k, où k est une constante. Ici, f(x) = 7 est bien une fonction constante.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0},{"id":72140,"question":"Quelle est la solution de l'équation 4x² - 12x + 9 = 0 ?","option_a":"x = 1,5","option_b":"x = 3","option_c":"x = -1,5","option_d":"x = 0","option_e":"","option_f":"","bonne_reponse":"A","explication":"En factorisant, on obtient (2x - 3)² = 0, donc la solution est x = 1,5 (double racine).","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0},{"id":72141,"question":"La fonction f(x) = 3x² - 2x + 1 est une fonction affine.","option_a":"Vrai","option_b":"Faux","option_c":"","option_d":"","option_e":"","option_f":"","bonne_reponse":"B","explication":"Une fonction affine doit être de degré 1. Ici, f(x) = 3x² - 2x + 1 est une fonction du second degré.","points":1,"type":"qcm","actif":1,"section_id":null,"ordre":0}]